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Weak normalisation theorem for typed lambdacalculusHi, There is something that seems strange to me. It says that: The degree &(T) of a type is defined by: The degree &(r) of a redex is defined by: Reading this it seems to me that a redex has the degree of its type. Am I wrong? Anyway, after it says: Note that, if r is a redex of type T, then &(r) > &(T). Why should &(r) be greater than &(T)? thanks, By ilSignorCarlo at 20071206 17:02  LtU Forum  previous forum topic  next forum topic  other blogs  3913 reads

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