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Prove: 'Cont r a = (a -> r) -> r' forms a monadI don't follow Haskell too much, and more often than not I disagree with Erik. However, this came up during an interview so it's supposedly something I should know.
Any takers? By marco at 2017-05-11 20:37 | LtU Forum | previous forum topic | next forum topic | other blogs | 6227 reads
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